2x^2=104^2

Solution for 2x^2=104^2 equation:

2x^2=104^2

We move all terms to the left:

2x^2-(104^2)=0

We add all the numbers together, and all the variables

2x^2-10816=0

a = 2; b = 0; c = -10816;
Δ = b2-4ac
Δ = 02-4·2·(-10816)
Δ = 86528
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{86528}=\sqrt{43264*2}=\sqrt{43264}*\sqrt{2}=208\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-208\sqrt{2}}{2*2}=\frac{0-208\sqrt{2}}{4}
=-\frac{208\sqrt{2}}{4}
=-52\sqrt{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+208\sqrt{2}}{2*2}=\frac{0+208\sqrt{2}}{4}
=\frac{208\sqrt{2}}{4}
=52\sqrt{2}
$